11 lines
		
	
	
	
		
			351 B
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			11 lines
		
	
	
	
		
			351 B
		
	
	
	
		
			Markdown
		
	
	
	
	
	
---
 | 
						|
categories:
 | 
						|
  - Logic
 | 
						|
tags: []
 | 
						|
---
 | 
						|
 | 
						|
# Biconditional introduction
 | 
						|
 | 
						|
The biconditional means if $P$ is the case, $Q$ must be the case and if $Q$ is the case, $P$ must be the case. Thus to introduce this operator we must demonstrate both that $Q$ follows from $P$ and that $P$ follows from $Q$. We do this via two sub-proofs.
 | 
						|
 | 
						|

 |