11 lines
283 B
Markdown
11 lines
283 B
Markdown
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# Biconditional Elimination
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Give that the biconditional means that if $P$ is the case, $Q$ must be the case
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and if $Q$ is the case, $P$ must be the case, if we have $P \leftrightarrow Q$
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and $P$, we can derive $Q$ and vice versa.
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