8 lines
349 B
Markdown
8 lines
349 B
Markdown
---
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categories:
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- Logic
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tags: [propositional_logic]
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---
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The biconditional means if $P$ is the case, $Q$ is the case and if $Q$ is the case, $P$ must be the case. Thus to introduce this operator we must demonstrate both that $Q$ follows from $P$ and that $P$ follows from $Q$. We do this via two sub-proofs.
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