5 KiB
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The C compilation process
C code is compiled to a binary executable in four stages:
- Preprocessing
- Compilation
- Assembly
- Linking
To demonstrate the output at the different stages I will compile the following simple program:
#include stdio.h
int main (void)
{
printf("Hello world!");
}
For standard compilation when you don't need to see all the interim stages, you just run the following in your source directory:
gcc main.c
gccstands for GNU C compiler. Actuallygccis a driver that orchestrates muliple tools:cc1, the actual C-to-assembly compiler;asthe assembler (assembly to object file); andldthe linker (linking the object files to the executable)
This generates:
a.out main.c
a.out is the executable binary.
To run this code:
./a.out
To compile to specified file name:
gcc -o hello_world main.c
Then to run:
./hello_world
Preprocessing
The processor finds all directives starting with # such as header file
include statements and adds them to your source code.
View this with:
gcc -E main.c
Here is an example for my script:
extern char *ctermid (char *__s) __attribute__ ((__nothrow__ , __leaf__))
__attribute__ ((__access__ (__write_only__, 1)));
# 931 "/usr/include/stdio.h" 3 4
extern void flockfile (FILE *__stream) __attribute__ ((__nothrow__ , __leaf__)) __attribute__ ((__nonnull__ (1)));
extern int ftrylockfile (FILE *__stream) __attribute__ ((__nothrow__ , __leaf__)) __attribute__ ((__nonnull__ (1)));
extern void funlockfile (FILE *__stream) __attribute__ ((__nothrow__ , __leaf__)) __attribute__ ((__nonnull__ (1)));
# 949 "/usr/include/stdio.h" 3 4
extern int __uflow (FILE *);
extern int __overflow (FILE *, int);
# 973 "/usr/include/stdio.h" 3 4
# 2 "main.c" 2
# 3 "main.c"
int main(void) { printf("Hello world"); }
Compilation
Takes the pre-processed source code and translates it into assembly language for your target architecture.
At this stage your code is assessed by the compiler for syntax errors and optimisation.
The result is human-readable assembly in a file called main.s
Create this with:
gcc -S main.c
Here is the output for my script:
.file "main.c"
.text
.section .rodata
.LC0:
.string "Hello world"
.text
.globl main
.type main, @function
main:
.LFB0:
.cfi_startproc
pushq %rbp
.cfi_def_cfa_offset 16
.cfi_offset 6, -16
movq %rsp, %rbp
.cfi_def_cfa_register 6
leaq .LC0(%rip), %rax
movq %rax, %rdi
movl $0, %eax
call printf@PLT
movl $0, %eax
popq %rbp
.cfi_def_cfa 7, 8
ret
.cfi_endproc
.LFE0:
.size main, .-main
.ident "GCC: (GNU) 15.2.1 20250813"
.section .note.GNU-stack,"",@progbits
Assembly
The assembly language code is converted into machine code. The output is an
object file (.o) which contains the machine code but is not yet executable
because it is not yet linked to the functions and variables that come from
imported code. Your object file is not yet combined with the object files of the
libraries and resources you have used.
Create just the object file with:
gcc -c main.c
As it is a binary file it is not human-readable. However you can us objdump to
view a more intelligble representation of the output.
objdump -dS main.o
main.o: file format elf64-x86-64
Disassembly of section .text:
0000000000000000 <main>:
#include <stdio.h>
int main(void) { printf("Hello world"); }
0: 55 push %rbp
1: 48 89 e5 mov %rsp,%rbp
4: 48 8d 05 00 00 00 00 lea 0x0(%rip),%rax # b <main+0xb>
b: 48 89 c7 mov %rax,%rdi
e: b8 00 00 00 00 mov $0x0,%eax
13: e8 00 00 00 00 call 18 <main+0x18>
18: b8 00 00 00 00 mov $0x0,%eax
1d: 5d pop %rbp
1e: c3 ret
To break this down:
- Left: the offset (address within this object file)
- Middle: the actual bytes - this is what the CPU reads and executes
- Right: the human-readable assembly, which is just a translation of those bytes
The assembly here is different to the assembly earlier in
main.s. This is because this time it is being interpreted after it has been written to machine code. It's a translation back from machine code to assembly.
Linking
In the final stage the object files are combined, resolving all the references
between them. The result of this stage will be the a.out file mentioned
earlier.
Different architectures
By default gcc will compile to whichever architecture it is being run on.
As I am using Linux x86-64, I get x86 machine code.
It is possible - although not trivial - to compile to different architectures
which use different instruction set.
Instructions sets other than the native machine you are running gcc on. This
is known as cross-compiling.
You might do this for ARM, say, and it would result in an ARM64 object file.