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python: set and dictionary comprehension

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thomasabishop 2023-09-13 07:43:58 +01:00
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Programming_Languages/Python/Syntax/List_comprehension_etc.md
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@ -70,7 +70,7 @@ print('new_list:', new_list)
By applying a condition (and no execution to each element) we effectively create a filter: By applying a condition (and no execution to each element) we effectively create a filter:
```py ```py
numbers = [1, 2, 3, 4, 5] numbers = [1, 2, 3, 4, 4, 4]
numbers_filtered = [i for i in numbers if i > 2] numbers_filtered = [i for i in numbers if i > 2]
print(numbers_filtered) print(numbers_filtered)
# [3, 4, 5] # [3, 4, 5]
@ -82,11 +82,23 @@ For comparison, the same outcome could be achieved with a filter and lambda:
with_filter = list(filter(lambda x: x > 2, numbers)) with_filter = list(filter(lambda x: x > 2, numbers))
print(with_filter) print(with_filter)
# [3, 4, 5] # [3, 4, 5]
``` ```
// TODO: Compare with how the same would be achieved with lambdas ## Set comprehension
We can also apply comprehension to sets. The syntax is practically identical but the difference is the resultant data structure will not contain duplicates.
```py
numbers = [1, 2, 3, 4, 4, 4]
unique = {i for i in numbers}
print(unique)
# {1,2,3,4}
```
## Dictionary comprehension ## Dictionary comprehension
// TODO: Add note on dictionary and set comprehension ```py
squares = {i: i * i for i in range(5)}
print(squares)
{0: 0, 1: 1, 2: 4, 3: 9, 4: 16, 5: 25}
```