eolas/zk/Logarithms.md

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---
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tags: [algebra]
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---
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Most simply a logarithm is a way of answering the question:
> How many of one number do we need to get another number. How many of x do we
> need to get y
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More formally:
> x raised to what power gives me y
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Below is an example of a logarithm:
$$
\log \_{3} 9
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$$
We read it:
> log base 3 of 9
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And it means:
> 3 raised to what power gives me 9?
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In this case the answer is easy: $3^2$ gives me nine, which is to say: three
multiplied by itself.
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## Using exponents to calculate logarithms
This approach becomes rapidly difficult when working with larger numbers. It's
not as obvious what $\log \_{5} 625$ would be using this method. For this
reason, we use exponents which are intimately related to logarithms.
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A logarithm can be expressed identically using exponents for example:
$$
\log \_{3} 9 = 2 \leftrightarrow 3^2 = 9
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$$
By carrying out the conversion in stages, we can work out the answer to the
question a logarithm poses.
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Let's work out $\log \_{2} 8$ using this method.
1. First we add a variable (x) to the expression on the right hand:
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$$
\log \_{2} 8 \leftrightarrow x
$$
1. Next we take the base of the logarithm and combine it with x as an exponent.
Now our formula looks like this:
$$
\log \_{2} 8 \leftrightarrow 2^x
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$$
1. Next we add an equals and the number that is left from the logarithm (8):
$$
\log \_{2} 8 \leftrightarrow 2^x = 8
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$$
Then the problem is reduced to: how many times do you need to multiply two by
itself to get 8? The answer is 3 : 2 x 2 x 2 or 2 p3. Hence we have the balanced
equation:
$$
\log \_{2} 8 \leftrightarrow 2^3 = 8
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$$
## Common base values
Often times a base won't be specified in a log expression. For example:
$$
\log1000
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$$
This is just a shorthand and it means that the base value is ten, i.e that the
logarithm is written in denary (base 10). So the above actually means:
$$
\log \_{10} 1000 = 3
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$$
This is referred to as the **common logarithm**
Another frequent base is Euler's number (approx. 2.71828) known as the **natural
logarithm**
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An example
$$
\log \_{e} 7.389 = 2
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$$