eolas/Logic/Proofs/Biconditional_Elimination.md

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---
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categories:
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- Logic
tags: [derivation-rules]
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---
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# Biconditional Elimination
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Give that the biconditional means that if $P$ is the case, $Q$ must be the case and if $Q$ is the case, $P$ must be the case, if we have $P \leftrightarrow Q$ and $P$, we can derive $Q$ and vice versa.
![](/_img/biconditional-elim.png)