---
tags:
  - Mathematics
  - Algebra
---

## Equivalent equations

 > 
 > Two equations are equivalent if they have the same [solution](Algebra%20key%20terms.md#678811) set.

We know from the distributive property of multiplication that the equation $a \cdot (b + c )$ is equivalent to $a \cdot b + a \cdot c$. If we assign values to the variables such that $b$ is $5$ and $c$ is $2$ we can demonstrate the equivalence that obtains in the case of the distributive property by showing that both $a \cdot (b + c )$ and $a \cdot b + a \cdot c$ have the same solution:

$$ 2 \cdot (5 + 2) = 14 $$

$$ 2 \cdot 5 + 2 \cdot 2 =14 $$

When we substitute $a$ with $2$ (the solution) we arrive at a true statement (the assertion that arrangement of values results in $14$). Since both expressions have the same solution they are equivalent.

## Creating equivalent equations

We can create equivalent equations by adding, subtracting, multiplying and dividing the *same quantity* from both sides of the equation (i.e. either side of the $=$ symbol).
Adding or subtracting the same quantity from both sides (either side of the $=$ ) of the equation results in an equivalent equation.

### Demonstration with addition

$$ x - 4 = 3 $$
The [solution](Algebra%20key%20terms.md#678811) to this equation is $7$
$$ x - 4 (+4) = 3 (+ 4)  $$

Here we have added $4$ to each side of the equation. If $x = 7$ then:

$$ 7 - 4 (+ 4) = 7 $$

and:

$$ 3 + 4 = 7 $$

### Demonstration with subtraction

$$ x + 4 = 9 $$
The [solution](Algebra%20key%20terms.md#678811) to this equation is $5$.
$$ x + 4 (-4) = 9(-4) $$

Here we have subtracted $4$ from each side of the equation. If $x = 5$ then:

$$ 5 + 4 (-4) = 5 $$

and

$$ 9 - 4 = 5 $$

### Demonstration with multiplication

$$x \cdot 2 = 10  $$
The [solution](Algebra%20key%20terms.md#678811) to this equation is $5$.
$$ (x \cdot 2) \cdot 3 = 10 \cdot 3 $$ 
Here we have multiplied each side of the equation by $3$. If $x =5$ then

$$ (5 \cdot 2) \cdot 3 = 30$$
$$ 10 \cdot 3 = 30$$

### Demonstration with division

$$x \cdot 3 = 18  $$
The [solution](Algebra%20key%20terms.md#678811) to this equation is $6$.
$$\frac{x \cdot 3}{3} = \frac{18}{3} $$
Here we have divided each side of the equation by $3$. If $x$ is 6, then
$$\frac{6 \cdot 3}{3} = 6$$
$$\frac{18}{3} = 6 $$
